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a car parts factory and an electronics factory use conveyor belts to mo…

Question

a car parts factory and an electronics factory use conveyor belts to move their products. the car parts conveyor belt stops for 2 seconds so workers can drill in bolts. how many meters long is the electronics factory conveyor belt? the electronics conveyor belt is _ meters long.

Explanation:

Step1: Find the speed of the car parts conveyor belt

The car parts conveyor belt moves \(10\) meters in \(2\) seconds (before the stop). The speed \(v=\frac{d}{t}\), where \(d = 10\) meters and \(t = 2\) seconds. So \(v=\frac{10}{2}=5\) m/s.

Step2: Analyze the motion of the electronics conveyor belt

The electronics conveyor belt has a constant - speed motion. We can use the speed formula \(d = vt\). From the graph, assume we use the non - stop part of the car parts belt's motion (since they are both conveyor belts, we can assume a relation based on the graph's proportion).
The electronics conveyor belt's motion: Let's consider the time - distance relationship. The slope of the electronics conveyor belt's graph (after \(t = 4\) s) has a constant speed. But another way: Since the car parts belt has a speed of \(5\) m/s (from \(d = 10\) m in \(t = 2\) s).
Looking at the electronics conveyor belt's graph, when \(t=5\) s, assume we use the fact that the motion is uniform (as it's a straight - line in the non - stop part of its graph). The speed of the electronics conveyor belt:
Take two points \((4,10)\) and \((6,14)\) for the car parts belt (after the stop, its speed is \(\frac{14 - 10}{6 - 4}=\frac{4}{2}=2\) m/s (but this is wrong, we should use the initial non - stop part).
Wait, correct approach: The car parts belt's non - stop speed (first \(2\) s) is \(v=\frac{10}{2} = 5\) m/s. The electronics conveyor belt:
Take the point when \(t = 5\) s. The electronics conveyor belt's length:
The speed of the electronics conveyor belt: From the graph, for the electronics conveyor belt, when \(t = 5\) s.
We know that the car parts belt's speed (non - stop) is \(v = 5\) m/s. But for the electronics conveyor belt, assume we use the formula \(d=vt\).
Looking at the graph, the electronics conveyor belt's motion is a straight line (uniform motion). Take two points \((0,0)\) and \((5,10)\) (wait no, the correct points: for the electronics conveyor belt (orange line), when \(t = 5\) s, \(d = 10\) m.

Answer:

\(10\)