Question

1. a car is initially travelling at a velocity of 4.2 m/s w. if the cars average acceleration is 0.86 m/s² w, how long will it take the car to reach a velocity of 9.6 m/s w? (2)

Explanation:

Step1: Identify the formula

Use the formula \(v = u+at\), where \(v\) is final velocity, \(u\) is initial velocity, \(a\) is acceleration and \(t\) is time.

Step2: Rearrange the formula for time

Rearrange \(v = u + at\) to \(t=\frac{v - u}{a}\).

Step3: Substitute the values

Given \(u = 4.2\space m/s\), \(v=9.6\space m/s\) and \(a = 0.86\space m/s^{2}\).
Substitute into \(t=\frac{v - u}{a}\), so \(t=\frac{9.6 - 4.2}{0.86}\).

Step4: Calculate the value

\(t=\frac{5.4}{0.86}\approx6.28\space s\)

Answer:

\(6.28\space s\)