Question

a car, initially traveling 24.0m/s speeds up at a rate of 4.00m/s² for 3.10s. determine all unknowns and answer the following questions.
what was the cars final speed?
unit
how far did the car travel during this time?
unit

Explanation:

Step1: Calculate final speed

Use the formula \(v = v_0+at\). Here \(v_0 = 24.0m/s\), \(a = 4.00m/s^{2}\), \(t = 3.10s\).
\(v=24.0 + 4.00\times3.10\)
\(v=24.0+12.4\)
\(v = 36.4m/s\)

Step2: Calculate distance traveled

Use the formula \(x=v_0t+\frac{1}{2}at^{2}\).
\(x=(24.0\times3.10)+\frac{1}{2}(4.00)(3.10)^{2}\)
First term: \(24.0\times3.10 = 74.4\)
Second term: \(\frac{1}{2}(4.00)(9.61)= 19.22\)
\(x=74.4 + 19.22\)
\(x=93.62m\)

Answer:

Final speed: \(36.4m/s\)
Distance traveled: \(93.62m\)