Question

a car dealership has a full car lot. 19 are red, 22 are blue, 7 are white, and 2 are yellow. find the probability that a car is not blue. p(not blue) = ? round your answer to the nearest hundredth.

Explanation:

Step1: Calculate total number of cars

First, we find the total number of cars by adding the number of cars of each color. The number of red cars is 19, blue is 22, white is 7, and yellow is 2. So the total number of cars \( n = 19 + 22 + 7 + 2 \).

$$ n=19 + 22+7 + 2=50 $$

Step2: Calculate number of non - blue cars

The number of blue cars is 22, so the number of non - blue cars \( m=19 + 7+2\) (since non - blue cars are red, white, and yellow).

$$ m = 19+7 + 2=28 $$

Step3: Calculate the probability of non - blue cars

The probability of an event is given by the formula \( P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). For the event of a car being non - blue, the number of favorable outcomes is the number of non - blue cars (\(m = 28\)) and the total number of outcomes is the total number of cars (\(n = 50\)). So \( P(\text{Not Blue})=\frac{28}{50}\).

$$ P(\text{Not Blue})=\frac{28}{50}=0.56 $$

Answer:

\(0.56\)