Question

6.3.1. calculate the volume of the tank.
=(l\times b\times h)
=(6m\times3m\times5m)
=(90m^{3})
6.3.2. given that (1m^{3}=1) kilolitre, convert the answer in 6.3.1 to kilolitres.
6.4. if (1cm^{3}=1ml), how many millilitres is there in (47000cm^{3})?

Explanation:

6.3.1

Step1: Recall the volume formula for a rectangular tank

The volume \(V\) of a rectangular tank (cuboid) is given by \(V = l\times b\times h\), where \(l\) is length, \(b\) is breadth, and \(h\) is depth.

Step2: Substitute the given values

Given \(l = 6m\), \(b = 3m\), \(h = 5m\). Then \(V=6\times3\times5\).

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6.3.2

Step1: Use the conversion factor

Given \(1m^{3}=1\) kilolitre. If the volume \(V = 90m^{3}\), then by substitution (since \(V\) (in kilolitres) \(=\frac{V\ (in\ m^{3})}{1m^{3}/\text{kilolitre}}\)), the volume in kilolitres is \(90\) kilolitres.

6.4

Step1: Use the given conversion factor

Given \(1cm^{3}=1ml\). If \(V = 47000cm^{3}\), then by substitution (since \(V\) (in \(ml\))=\(V\ (in\ cm^{3})\times\frac{1ml}{1cm^{3}}\)), we have \(V = 47000ml\).

Answer:

6.3.1: \(90m^{3}\)
6.3.2: \(90\) kilolitres
6.4: \(47000ml\)