Question

calculate the energy of a photon traveling with a frequency of 1.0 x 10^5 s^-1. 6.6 x10^-29 joules 6.6 x10^29 joules 6.6 x10^-39 joules 0.15 x 10^39 joules

Explanation:

Step1: Recall Planck's equation

The energy of a photon is given by $E = h
u$, where $h$ is Planck's constant ($h=6.63\times 10^{-34}\text{ J}\cdot\text{s}$) and $
u$ is the frequency of the photon.

Step2: Substitute values

We are given $
u = 1.0\times 10^{5}\text{ s}^{-1}$. Substitute $h = 6.63\times 10^{-34}\text{ J}\cdot\text{s}$ and $
u=1.0\times 10^{5}\text{ s}^{-1}$ into the formula $E = h
u$. So $E=(6.63\times 10^{-34}\text{ J}\cdot\text{s})\times(1.0\times 10^{5}\text{ s}^{-1})$.

Step3: Calculate the result

Using the rule of exponents $a^{m}\times a^{n}=a^{m + n}$, we have $E = 6.63\times10^{-34 + 5}\text{ J}=6.63\times 10^{-29}\text{ J}\approx6.6\times 10^{-29}\text{ J}$.

Answer:

$6.6\times 10^{-29}$ Joules (the second - option in the multiple - choice list)