QUESTION IMAGE
Question
- calculate: $(81)^{\frac{1}{2}}$;
a. 9
b. 54
c. 3
d. 27
Step1: Recall the exponent rule
The exponent rule for a fractional exponent \(\frac{1}{n}\) means taking the \(n\)-th root. So, \((81)^{\frac{1}{4}}\) is the 4th root of 81.
Step2: Find the 4th root of 81
We know that \(3^4 = 81\) (since \(3\times3\times3\times3 = 81\)). So, the 4th root of 81 is 3? Wait, no, wait. Wait, \(9^2=81\), but \(3^4 = 81\). Wait, \((81)^{\frac{1}{4}}=\sqrt[4]{81}\). Let's check: \(3^4 = 81\), so \(\sqrt[4]{81}=3\)? Wait, no, \(9^2 = 81\), but \(3^4=(3^2)^2 = 9^2 = 81\). So \(\sqrt[4]{81}=3\)? Wait, no, wait, \(9\) is \(3^2\), so \(9^2 = 81\), but \(3^4 = 81\). So the 4th root of 81 is 3? Wait, no, wait, \(3^4 = 81\), so \(\sqrt[4]{81}=3\). Wait, but also, \((-3)^4 = 81\), but since we are dealing with real numbers and the principal root, we take the positive one. Wait, but wait, the options have 9, 54, 3, 27. Wait, maybe I made a mistake. Wait, \(9^2 = 81\), so \(\sqrt{81}=9\), but \((81)^{\frac{1}{4}}\) is the 4th root. Wait, \(3^4 = 81\), so \(\sqrt[4]{81}=3\)? Wait, no, \(9\) is \(3^2\), so \(9^2 = 81\), so \((9)^{\frac{1}{2}} = 3\), but \((81)^{\frac{1}{4}}=(9^2)^{\frac{1}{4}}=9^{\frac{2}{4}}=9^{\frac{1}{2}} = 3\)? Wait, no, that's not right. Wait, \((81)^{\frac{1}{4}}=\sqrt[4]{81}\). Let's calculate \(3^4 = 81\), so \(\sqrt[4]{81}=3\). But the option a is 9, c is 3. Wait, maybe I messed up. Wait, \(9^2 = 81\), so \(\sqrt{81}=9\), but \((81)^{\frac{1}{4}}\) is the 4th root. Wait, \(3^4 = 81\), so \(\sqrt[4]{81}=3\). But let's check the options. Option c is 3, option a is 9. Wait, maybe the exponent is \(\frac{1}{2}\)? Wait, the problem says \((81)^{\frac{1}{4}}\)? Wait, maybe it's a typo, and it's \((81)^{\frac{1}{2}}\)? If it's \((81)^{\frac{1}{2}}\), then it's 9. But the problem says \(\frac{1}{4}\). Wait, let's re - check. \(3^4 = 81\), so \(\sqrt[4]{81}=3\). So the answer should be c. 3? Wait, but let's confirm. \(3\times3\times3\times3 = 81\), so the 4th root of 81 is 3. So the correct option is c. 3.
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c. 3