Question

bookends the books are held up with bookends in the shape of triangles. if $m\angle 1 = 62^{\circ}$, what is $m\angle 2$?

Explanation:

Step1: Recall the sum of angles in a right - triangle

In a right - triangle, the sum of the two non - right angles is \(90^{\circ}\). Let \(\angle1\) and \(\angle2\) be the two non - right angles of the right - triangle. So, \(m\angle1 + m\angle2=90^{\circ}\).

Step2: Solve for \(m\angle2\)

Given \(m\angle1 = 62^{\circ}\), substitute into the equation \(m\angle1 + m\angle2=90^{\circ}\). Then \(m\angle2=90^{\circ}-m\angle1\).
Substitute \(m\angle1 = 62^{\circ}\) into the formula: \(m\angle2 = 90^{\circ}-62^{\circ}\).

$$m\angle2=28^{\circ}$$

Answer:

\(28^{\circ}\)