Question

a board game uses the deck of 20 cards shown to the right. two cards are selected at random from this deck. calculate the probability of selecting a monkey on the first draw and a frog on the second draw, both with and without replacement.
two cards are to be selected without replacement. determine the probability the first card selected shows a monkey and the second shows a frog.
(type an integer or a simplified fraction.)

Explanation:

Answer:

There are 5 monkeys and 5 frogs in the 20 - card deck.
The probability that the first card shows a monkey is $\frac{5}{20}=\frac{1}{4}$.
After the first - card draw (without replacement), there are 19 cards left, and 5 frogs.
The probability that the second card shows a frog given that the first card shows a monkey is $\frac{5}{19}$.
The probability that the first card shows a monkey and the second card shows a frog is $\frac{1}{4}\times\frac{5}{19}=\frac{5}{76}$