Question

becky went for a walk in the rain, and one of her 600-gram rain boots got covered in mud. to clean her rain boot, becky washed it in a bucket with 800 grams of water. after a few seconds, becky noticed a change. her 600-gram rain boot was clean. the bucket was filled with 1,000 grams of muddy water. complete the bar graph to show the mass of the mud. masses before and after the change

Explanation:

Step1: Apply conservation of mass

The total mass before cleaning should equal the total mass after cleaning. Before: rain boot (600g) + water (800g) + mud (let mass be \( m \)) = \( 600 + 800 + m \). After: rain boot (600g) + muddy water (1000g) = \( 600 + 1000 \). So, \( 600 + 800 + m = 600 + 1000 \).

Step2: Solve for mud mass

Simplify the equation: \( 1400 + m = 1600 \). Subtract 1400 from both sides: \( m = 1600 - 1400 = 200 \) grams. So the mud bar should reach 200 grams on the graph.

Answer:

The mass of the mud is 200 grams, so the bar for mud in the graph should be drawn to the 200 - gram mark.