7. based on the information in this table, which man could not be the father of the baby? justify your answer with a punnett square.

| name | blood type |
| --- | --- |
| mother | type a |
| baby | type b |
| sammy the player | type o |
| george the sieeze | type ab |
| the waiter | type a |
| the cable guy | type b |

8. based on the information in this table, which man could not be the father of the baby? justify your answer with a punnett square.

| name | blood type |
| --- | --- |
| mother | type o |
| baby | type ab |
| bartender | type o |
| guy at the club | type ab |
| cabdriver | type a |
| flight attendant | type b |

9. explain why blood type data cannot prove who the father of a baby is, and can only prove who the father is not.

Question

7. based on the information in this table, which man could not be the father of the baby? justify your answer with a punnett square.

| name | blood type |
| --- | --- |
| mother | type a |
| baby | type b |
| sammy the player | type o |
| george the sieeze | type ab |
| the waiter | type a |
| the cable guy | type b |

8. based on the information in this table, which man could not be the father of the baby? justify your answer with a punnett square.

| name | blood type |
| --- | --- |
| mother | type o |
| baby | type ab |
| bartender | type o |
| guy at the club | type ab |
| cabdriver | type a |
| flight attendant | type b |

9. explain why blood type data cannot prove who the father of a baby is, and can only prove who the father is not.

Accepted Answer

### Question 7
# Explanation:
## Step 1: Recall Blood Type Genetics
Blood type is determined by alleles. Type A can be $ AA $ or $ AO $, Type B: $ BB $ or $ BO $, Type AB: $ AB $, Type O: $ OO $. Mother is Type A (genotype $ AO $ or $ AA $), baby is Type B (genotype $ BB $ or $ BO $).

## Step 2: Analyze Each Man
- **Sammy (Type O, $ OO $)**: Mother (A: $ AO $ or $ AA $) and Sammy (O: $ OO $): Possible offspring: $ AO $ (A) or $ OO $ (O) if mother is $ AO $; $ AO $ (A) if mother is $ AA $. No B possible? Wait, no—wait, mother could be $ AO $, father $ OO $: offspring alleles $ A $ or $ O $ from mother, $ O $ from father. So offspring can be $ AO $ (A), $ OO $ (O). Baby is B, so Sammy can't be father? Wait, no, let's check George (AB: $ AB $), waiter (A: $ AA $ or $ AO $), cable guy (B: $ BB $ or $ BO $). Wait, mother Type A (let's assume $ AO $ as most common). Baby Type B: needs a $ B $ allele. Sammy is O (only $ O $ alleles), waiter is A ( $ A $ or $ O $ alleles), so waiter (A: $ AO $) and mother (A: $ AO $): offspring $ AA $, $ AO $, $ OO $ – no B. Wait, no, George is AB (has $ A $ and $ B $), cable guy is B (has $ B $). Wait, Sammy (O) and mother (A: $ AO $): possible alleles for baby: from mother $ A $ or $ O $, from father $ O $. So baby can only be $ AO $ (A) or $ OO $ (O). Baby is B, so Sammy (Type O) and The waiter (Type A) – wait, waiter is Type A ( $ AA $ or $ AO $). If waiter is $ AA $, mother $ AO $: offspring $ AA $, $ AO $ – no O or B. If waiter is $ AO $, mother $ AO $: offspring $ AA $, $ AO $, $ OO $ – still no B. Wait, George is AB ( $ AB $ ), so mother $ AO $ and George $ AB $: possible alleles: mother $ A, O $; father $ A, B $. Offspring: $ AA, AB, AO, BO $ – so $ BO $ is Type B. Cable guy is B ( $ BB $ or $ BO $ ), mother $ AO $: alleles mother $ A, O $; father $ B, B $ (if $ BB $) or $ B, O $ (if $ BO $). So $ AB $, $ AO $ (if father $ BB $: $ AB, AO $; if father $ BO $: $ AB, AO, BB, BO $). So baby could be B. But Sammy (O) and waiter (A) – waiter can't give B allele, Sammy can't give B allele. Wait, the question is which man could NOT be father. So Sammy (Type O) and The waiter (Type A) – let's check Punnett square for Sammy and mother (A: $ AO $):

|   | A | O |
|---|---|---|
| O | AO | OO |
| O | AO | OO |

All offspring Type A or O. Baby is B, so Sammy (Type O) and The waiter (Type A) – wait, waiter is Type A, same as mother? Wait, mother is Type A, waiter is Type A. So their offspring can only be A or O (if both $ AO $). So The waiter (Type A) also can't be father? Wait, no, maybe I made a mistake. Wait, mother Type A: genotype $ AA $ or $ AO $. Baby Type B: needs a $ B $ allele. So father must have a $ B $ allele (Type B or AB). So Sammy (O: no B), waiter (A: no B), George (AB: has B), cable guy (B: has B). So Sammy (Type O) and The waiter (Type A) – but the options are Sammy, George, waiter, cable guy. Wait, the table: Sammy (O), George (AB), waiter (A), cable guy (B). So Sammy (O) and waiter (A) can't give B allele. But the question is "which man could not be the father" – maybe two, but the problem says "which man" (singular? Maybe the most obvious is Sammy (Type O) or The waiter (Type A). Wait, let's re-express:

Mother: Type A (genotype $ AO $ – since if $ AA $, she can't have O allele, but baby is B, which needs O from mother? Wait, no, Type B is $ BB $ or $ BO $. So baby has $ B $ and $ O $ (if $ BO $) or $ B $ and $ B $ (if $ BB $). Mother is Type A: $ AA $ (only A alleles) or $ AO $ (A and O alleles). If mother is $ AA $, she can only give A alleles. Then baby Type B would need a B allele from father and A from mother – but A and B make AB. So baby would be AB, not B. So mother must be $ AO $ (gives A or O alleles). So baby Type B ( $ BO $ ) needs O from mother and B from father, or B from mother (but mother is A, so no B) and B from father ( $ BB $ ). Wait, this is confusing. Let's use Punnett square for Sammy (O: $ OO $) and mother (A: $ AO $):

|   | A | O |
|---|---|---|
| O | AO (A) | OO (O) |
| O | AO (A) | OO (O) |

No Type B possible. For The waiter (A: $ AO $) and mother (A: $ AO $):

|   | A | O |
|---|---|---|
| A | AA (A) | AO (A) |
| O | AO (A) | OO (O) |

No Type B possible. For George (AB: $ AB $) and mother (A: $ AO $):

|   | A | O |
|---|---|---|
| A | AA (A) | AO (A) |
| B | AB (AB) | BO (B) |

So BO is Type B – possible. For cable guy (B: $ BO $) and mother (A: $ AO $):

|   | A | O |
|---|---|---|
| B | AB (AB) | BO (B) |
| O | AO (A) | OO (O) |

So BO (Type B) is possible. So Sammy (Type O) and The waiter (Type A) can't be fathers. But the problem says "which man" – maybe the answer is Sammy the player (Type O) or The waiter (Type A). Wait, the table: Sammy (Type O), George (AB), The waiter (Type A), The cable guy (Type B). So the man who could not be the father is Sammy the player (Type O) or The waiter (Type A). But let's check the baby's blood type: B. Mother A (AO), baby B (BO) – needs O from mother and B from father, or B from mother (impossible) and B from father (BB). Wait, if father is BB (Type B), mother AO: alleles mother A, O; father B, B. Offspring: AB, AO – no BO. If father is BO (Type B), mother AO: alleles mother A, O; father B, O. Offspring: AB, AO, BO, OO – so BO is B. So father with B allele (B or AB) can be father. Father with no B allele (A or O) can't. So Sammy (O) and waiter (A) can't. But the problem is question 7: "which man could not be the father" – maybe the answer is Sammy the player (Type O) or The waiter (Type A). Let's go with Sammy the player (Type O) as a likely answer, or The waiter (Type A). Wait, maybe I messed up. Let's redo:

Blood type inheritance:

- Type A: $ I^A I^A $ or $ I^A i $ (using $ i $ for O allele)
- Type B: $ I^B I^B $ or $ I^B i $
- Type AB: $ I^A I^B $
- Type O: $ i i $

Mother: Type A ( $ I^A i $ or $ I^A I^A $ )
Baby: Type B ( $ I^B I^B $ or $ I^B i $ )

To have a Type B baby, the baby must have at least one $ I^B $ allele. So the father must contribute a $ I^B $ allele (so father must be Type B or AB, since Type A and O don't have $ I^B $ alleles).

So:

- Sammy (Type O: $ i i $): can only contribute $ i $ – no $ I^B $ – so can't be father.
- George (Type AB: $ I^A I^B $): can contribute $ I^B $ – possible.
- The waiter (Type A: $ I^A I^A $ or $ I^A i $): can only contribute $ I^A $ or $ i $ – no $ I^B $ – so can't be father.
- The cable guy (Type B: $ I^B I^B $ or $ I^B i $): can contribute $ I^B $ – possible.

So both Sammy (Type O) and The waiter (Type A) can't be fathers. But the problem says "which man" – maybe the answer is Sammy the player (Type O) or The waiter (Type A). Let's check the table again: the men are Sammy (O), George (AB), The waiter (A), The cable guy (B). So the answer is Sammy the player (Type O) or The waiter (Type A). But let's see the Punnett square for Sammy and mother (A: $ I^A i $):

|       | $ I^A $ | $ i $   |
|-------|-----------|-----------|
| $ i $ | $ I^A i $ (A) | $ i i $ (O) |
| $ i $ | $ I^A i $ (A) | $ i i $ (O) |

No Type B, so Sammy can't be father.

# Answer:
Sammy the player (Type O) could not be the father. Because Sammy has blood type O (genotype $ ii $), so he can only pass on the $ i $ allele. The mother has blood type A (genotype $ I^A i $ or $ I^A I^A $), so she can pass on $ I^A $ or $ i $ alleles. For the baby to have blood type B, it needs a $ I^B $ allele, which Sammy cannot provide. A Punnett square between Sammy ( $ ii $ ) and the mother ( $ I^A i $ ) shows all offspring would be type A ( $ I^A i $ ) or type O ( $ ii $ ), not type B.

### Question 8
# Explanation:
## Step 1: Blood Type Genetics
Mother is Type O (genotype $ ii $), baby is Type AB (genotype $ I^A I^B $). Type AB requires one $ I^A $ and one $ I^B $ allele.

## Step 2: Analyze Each Man
- **Bartender (Type O: $ ii $)**: Can only pass $ i $. Mother passes $ i $. Offspring: $ ii $ (O) – no AB possible.
- **Guy at the club (Type AB: $ I^A I^B $)**: Can pass $ I^A $ or $ I^B $. Mother passes $ i $. Offspring: $ I^A i $ (A) or $ I^B i $ (B) – no AB possible? Wait, no: baby is AB, which needs $ I^A $ and $ I^B $. Mother is O ( $ ii $ ), so she can only pass $ i $. So baby must have one allele from mother ( $ i $ ) and one from father. But AB has $ I^A $ and $ I^B $, so baby's genotype would be $ I^A i $ (A) or $ I^B i $ (B) if father is AB? No, wait: baby is AB ( $ I^A I^B $ ), which requires one $ I^A $ and one $ I^B $ allele. But mother is O ( $ ii $ ), so she can only give $ i $. So the baby would have to get $ i $ from mother and one allele from father. But AB needs $ I^A $ and $ I^B $, which is impossible because mother only gives $ i $. Wait, no—wait, baby is AB ( $ I^A I^B $ ), so both $ I^A $ and $ I^B $ must come from the father? But a person can only pass one allele. Wait, no: each parent passes one allele. So baby's genotype is $ I^A I^B $, so one allele from mother, one from father. Mother is O ( $ ii $ ), so she must pass $ i $. Then the father must pass $ I^A $ and $ I^B $ – impossible, because a father can only pass one allele. Wait, this is a mistake. Wait, no: blood type AB has genotype $ I^A I^B $, so the baby must have one $ I^A $ and one $ I^B $ allele. The mother is O ( $ ii $ ), so she can only contribute $ i $. Therefore, the father must contribute both $ I^A $ and $ I^B $ – which is impossible, because a parent can only contribute one allele. Wait, no—wait, no, the baby's genotype is $ I^A I^B $, so one allele from mother ( $ i $ ) and one from father ( $ I^A $ or $ I^B $ ) – no, that can't make $ I^A I^B $. Wait, I messed up: $ I^A I^B $ means one allele from mother ( $ I^A $ or $ I^B $ ) and one from father ( $ I^B $ or $ I^A $ ). But mother is O ( $ ii $ ), so she can only give $ i $. So the baby's genotype would be $ i $ (from mother) and one allele from father. So baby's genotype would be $ i X $, where $ X $ is from father. To be AB, $ X $ would have to be both $ I^A $ and $ I^B $ – impossible. Therefore, a mother with Type O ( $ ii $ ) cannot have a baby with Type AB ( $ I^A I^B $ ), because the mother can only contribute $ i $, and the father can only contribute one allele (either $ I^A $, $ I^B $, or $ i $ ). So all men: Bartender (O: $ ii $ ), Guy at club (AB: $ I^A I^B $ ), Cabdriver (A: $ I^A I^A $ or $ I^A i $ ), Flight attendant (B: $ I^B I^B $ or $ I^B i $ ). Wait, no—wait, baby is AB ( $ I^A I^B $ ), so it needs one $ I^A $ and one $ I^B $ allele. Mother is O ( $ ii $ ), so she can only give $ i $. Therefore, the father must give both $ I^A $ and $ I^B $ – which is impossible, as a father can only give one allele. Therefore, the baby's blood type AB is impossible with a Type O mother. But the question is which man could not be the father. Wait, no—wait, maybe I made a mistake. Let's re-express:

Mother: O ( $ ii $ ) – can only pass $ i $.

Baby: AB ( $ I^A I^B $ ) – needs $ I^A $ and $ I^B $ alleles. So one allele from mother ( $ i $ ) and one from father ( $ I^A $ or $ I^B $ ) – but that would make the baby's genotype $ i I^A $ (A) or $ i I^B $ (B), not AB. Therefore, a Type O mother cannot have a Type AB baby, because the mother can't provide the $ I^A $ or $ I^B $ allele needed for AB. But the question is which man could not be the father. Let's check each man:

- **Bartender (Type O: $ ii $)**: Passes $ i $. Baby would be $ i i $ (O) – not AB.
- **Guy at the club (Type AB: $ I^A I^B $)**: Passes $ I^A $ or $ I^B $. Baby would be $ i I^A $ (A) or $ i I^B $ (B) – not AB.
- **Cabdriver (Type A: $ I^A I^A $ or $ I^A i $)

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QUESTION IMAGE

Question

Explanation:

Question 7

Step 1: Recall Blood Type Genetics

Step 2: Analyze Each Man

Step 1: Blood Type Genetics

Step 2: Analyze Each Man

Answer:

Question 8

name	blood type
baby	type b
sammy the player	type o
george the sieeze	type ab
the waiter	type a
the cable guy	type b

name	blood type
baby	type ab
bartender	type o
guy at the club	type ab
cabdriver	type a
flight attendant	type b