Question

based on the information in the table, which linear equation best predicts salary, s based on years of experience, y?
s = 2,762y + 49,857
s = 2,909y + 50,091
s = 2,667y + 50,333
s = 2,429y + 50,857

Explanation:

Step1: Calculate the slope ($m$)

The formula for slope $m=\frac{y_2 - y_1}{x_2 - x_1}$. Let's take two points $(y_1,S_1)=(1,53000)$ and $(y_2,S_2)=(12,85000)$.
$m=\frac{85000 - 53000}{12 - 1}=\frac{32000}{11}\approx2909$

Step2: Use the point - slope form $S - S_1=m(y - y_1)$

Using the point $(y_1,S_1)=(1,53000)$ and $m = 2909$.
$S-53000=2909(y - 1)$
$S=2909y-2909 + 53000$
$S=2909y+50091$

Answer:

$S = 2,909y+50,091$