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a bag contains 42 red, 45 green, 20 yellow, and 32 purple candy. you pi…

Question

a bag contains 42 red, 45 green, 20 yellow, and 32 purple candy. you pick one candy at random. find the probability that it is green or yellow. p(green or yellow) = \frac{?}{}

Explanation:

Step1: Calculate total number of candies

$$42 + 45+20 + 32=139$$

Step2: Calculate number of green or yellow candies

$$45 + 20=65$$

Step3: Calculate the probability

Probability formula: $P(A)=\frac{n(A)}{n(S)}$, where $n(A)$ is the number of favorable outcomes and $n(S)$ is the total number of outcomes. So $P(\text{green or yellow})=\frac{65}{139}$

Answer:

$\frac{65}{139}$