Question

the average temperatures for two of the worlds hottest places are given. determine which location has the warmer average temperature and by how many degrees fahrenheit. location a: 86.8°f and location b: 30.2°c the location with the warmer average temperature is which is warmer by about °f. (round to the nearest tenth of a degree as needed.)

Explanation:

Step1: Convert Celsius to Fahrenheit

The formula to convert Celsius to Fahrenheit is $F = \frac{9}{5}C + 32$. For Location B with $C = 30.2^\circ$, we substitute:
$F=\frac{9}{5}\times30.2 + 32$
First, calculate $\frac{9}{5}\times30.2 = 54.36$. Then add 32: $54.36 + 32 = 86.36^\circ$F.

Step2: Compare temperatures

Location A is $86.8^\circ$F and Location B is $86.36^\circ$F. Since $86.8>86.36$, Location A is warmer.

Step3: Find the difference

Subtract the temperature of Location B from Location A: $86.8 - 86.36 = 0.44^\circ$F. Rounding to the nearest tenth gives $0.4^\circ$F.

Answer:

The location with the warmer average temperature is Location A, which is warmer by about $0.4^\circ$F.