QUESTION IMAGE
Question
assume that the set of given information is true. use the law of syllogism to write a conditional.
if a baby is feeling nauseous, then the baby is ill.
if a baby is ill, then the baby must be brought to the physician’s office.
choose the correct conditional below
a. if a baby is brought to the physician’s office, then the baby must be feeling nauseous.
b. if a baby is not brought to the physician’s office, then the baby is not ill.
c. if a baby is feeling nauseous, then the baby is not ill.
d. if a baby is not ill, then the baby is not feeling nauseous.
e. if a baby is brought to the physician’s office, then the baby is ill.
f. if a baby is not feeling nauseous, then the baby is not ill.
g. if a baby is feeling nauseous, then the baby must be brought to the physician’s office.
help me solve this
Step1: Recall the Law of Syllogism
The Law of Syllogism states that if we have two conditionals \( p \to q \) and \( q \to r \), then we can conclude \( p \to r \).
Let \( p \): "a baby is feeling nauseous", \( q \): "the baby is ill", \( r \): "the baby must be brought to the physician’s office".
The first conditional is \( p \to q \) (If a baby is feeling nauseous, then the baby is ill), and the second is \( q \to r \) (If a baby is ill, then the baby must be brought to the physician’s office).
Step2: Apply the Law of Syllogism
Using the Law of Syllogism, we combine \( p \to q \) and \( q \to r \) to get \( p \to r \). Translating back, this means "If a baby is feeling nauseous, then the baby must be brought to the physician’s office".
Now let's analyze each option:
- Option A: This is \( r \to p \), which is not a valid conclusion from the given conditionals (affirming the consequent).
- Option B: This is \(
eg r \to
eg q \), which is the contrapositive of \( q \to r \), but not the conclusion from the Law of Syllogism.
- Option C: This contradicts the first conditional \( p \to q \).
- Option D: This is the contrapositive of \( p \to q \) ( \(
eg q \to
eg p \) ), not the syllogism conclusion.
- Option E: This is \( r \to q \), which is not a valid conclusion (affirming the consequent of \( q \to r \)).
- Option F: This is \(
eg p \to
eg q \), which is not a valid conclusion from the syllogism.
- Option G: This is \( p \to r \), which matches the conclusion from the Law of Syllogism.
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G. If a baby is feeling nauseous, then the baby must be brought to the physician's office.