Question

assume that a randomly selected subject is given a bone density test. those test scores are normally distributed with a mean of 0 and a standard deviation of 1. find the probability that a given score is less than - 1.31 and draw a sketch of the region.
sketch the region. choose the correct graph below.
the probability is ■.
(round to four decimal places as needed.)

Explanation:

Step1: Use the standard normal distribution table

The probability that \(Z < - 1.31\) can be found using the standard - normal distribution table (also known as the \(z\) - table). The \(z\) - table gives the cumulative probability \(P(Z < z)\) for a given \(z\) - score.

Step2: Look up the value in the \(z\) - table

For \(z=-1.31\), we look at the row corresponding to \(z = - 1.3\) and the column corresponding to \(0.01\). In the standard normal table, the value at the intersection of the row \(z=-1.3\) and column \(z = 0.01\) is \(0.0951\).

Answer:

\(0.0951\)