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assume that a procedure yields a binomial distribution with ( n = 8 ) t…

Question

assume that a procedure yields a binomial distribution with ( n = 8 ) trials and a probability of success of ( p = 0.30 ). use a binomial probability table to find the probability that the number of successes ( x ) is exactly 4. click on the icon to view the binomial probabilities table. ( p(4)=square ) (round to three decimal places as needed)

Explanation:

Step1: Recall binomial probability formula

The binomial probability formula is \(P(X = k)=C(n,k)\times p^{k}\times(1 - p)^{n - k}\), where \(C(n,k)=\frac{n!}{k!(n - k)!}\), \(n = 8\), \(k = 4\), \(p=0.3\), and \(1-p = 0.7\).

Step2: Calculate combination \(C(8,4)\)

$$ LATEXBLOCK0 $$

Step3: Calculate \(p^{k}\) and \((1 - p)^{n - k}\)

\(p^{k}=(0.3)^{4}=0.0081\), \((1 - p)^{n - k}=(0.7)^{4}=0.2401\)

Step4: Calculate \(P(X = 4)\)

$$ LATEXBLOCK1 $$

Answer:

\(0.136\)