Question

the area of a rectangle is 56.96 m². if the length is 16 m, what is its perimeter? how can we solve for the area of a rectangle? a = l × w a = l + w a = l + l + w + w a = l × l × w × w

Explanation:

Step1: Find the width

The formula for the area of a rectangle is \(A = L\times W\). Given \(A = 56.96\space m^{2}\) and \(L = 16\space m\), we can solve for \(W\) by \(W=\frac{A}{L}\).

$$W=\frac{56.96}{16}= 3.56\space m$$

Step2: Calculate the perimeter

The formula for the perimeter of a rectangle is \(P=2(L + W)\). Substitute \(L = 16\space m\) and \(W = 3.56\space m\) into the formula.

$$P=2(16 + 3.56)=2\times19.56 = 39.12\space m$$

Answer:

The perimeter of the rectangle is \(39.12\space m\)