Question

anytime i cross a heterozygous individual with a homozygous individual, the box i use is...
2×1
4×4
1×1
2×2

Explanation:

To determine the Punnett square for crossing a heterozygous (e.g., Aa) and homozygous (e.g., AA or aa) individual: A heterozygous individual has 2 types of gametes, and a homozygous has 1 type. The Punnett square rows/columns correspond to gametes. So, rows (from one parent) and columns (from the other) give a \(2\times1\) grid (since one parent has 2 gametes, the other 1).

Answer:

A. \(2 \times 1\)