Question

analyze this: a rightward force of 354 n is applied to a 12.1 - kg object to accelerate it to the right at 12.1 m/s/s. complete the diagram.
tap on a field to enter or edit its value.
units
force: n
mass: kg
acceln: m/s/s

Explanation:

Step1: Calculate \(F_{grav}\)

Using \(F_{grav}=mg\) (\(g = 9.8\ m/s^{2}\)), \(F_{grav}=12.1\times9.8=118.58\ N\)

Step2: Determine \(F_{norm}\)

Since there is no vertical acceleration (\(a_y = 0\)), \(F_{norm}=F_{grav}\), so \(F_{norm}=118.58\ N\)

Step3: Find \(F_{net}\)

Using \(F_{net}=ma\), \(F_{net}=12.1\times12.1 = 146.41\ N\)

Step4: Calculate \(F_{frict}\)

Using \(F_{net}=F_{app}-F_{frict}\), then \(F_{frict}=F_{app}-F_{net}\). Given \(F_{app}=354\ N\), \(F_{frict}=354 - 146.41=207.59\ N\)

Answer:

\(F_{norm}=118.58\ N\), \(F_{frict}=207.59\ N\), \(F_{grav}=118.58\ N\), \(m = 12.1\ kg\), \(a=12.1\ m/s^{2}\), \(F_{net}=146.41\ N\)