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Question
ambe group of schools, vadodara
harni, waghodia road & manjalpur
english medium year : 2025 - 26
assignment - 4 (semester - i)
sub. : math
class: vii
date : 10 - 09 - 25
date of submission : 16 - 09 - 25
l - 5
l - 5
✶ fill in the blanks.
- a line segment has ______ end point.
- the supplementary angle of 45° is ______.
- ______ angle is formed when one arm is common and remaining two arms are on either side.
- if a line is a transversal to three lines then ____ points of intersections will be formed.
- the complementary angle of 54° is ______.
- the measure of right angle is ______.
✶ do as directed.
- name the pair of angles in each figure.
(a)
(b)
(c)
(d)
- find the angle which is equal to its supplement.
✶ in the adjoining figure, identify the following.
- the pair of alternate interior angles.
- the pair of corresponding angles.
- the vertically opposite angles.
✶ find the value of x in the following figure if l||m.
1)
2)
3)
4)
✶ an angle is greater than 90°. is its supplementary angle greater than 90° or equal to 90° or less than 90°? justify.
Fill - in - the - blanks:
1.
A line segment has two endpoints. This is a basic definition in geometry.
2.
The supplementary angle of an angle $\theta$ is $180^{\circ}-\theta$. For $\theta = 45^{\circ}$, the supplementary angle is $180 - 45=135^{\circ}$.
3.
A linear - pair angle is formed when one arm is common and the remaining two arms are on either side.
4.
If a line is a transversal to three lines, then three points of intersections will be formed.
5.
The complementary angle of an angle $\alpha$ is $90^{\circ}-\alpha$. For $\alpha = 54^{\circ}$, the complementary angle is $90 - 54 = 36^{\circ}$.
6.
The measure of a right - angle is $90^{\circ}$.
Do as directed:
1.
(a)
$\angle1$ and $\angle2$ are corresponding angles.
(b)
$\angle3$ and $\angle4$ are vertically opposite angles.
(c)
$\angle5$ and $\angle6$ are alternate interior angles.
(d)
$\angle7$ and $\angle8$ are adjacent angles.
2.
Let the angle be $x$. Its supplement is $180 - x$. If the angle is equal to its supplement, then $x=180 - x$.
Step1: Add $x$ to both sides
$x+x=180 - x+x$
$2x = 180$
Step2: Divide both sides by 2
$x=\frac{180}{2}=90^{\circ}$
In the adjoining figure:
1.
The pair of alternate interior angles are $\angle3$ and $\angle5$, $\angle4$ and $\angle6$.
2.
The pair of corresponding angles are $\angle1$ and $\angle5$, $\angle2$ and $\angle6$, $\angle3$ and $\angle7$, $\angle4$ and $\angle8$.
3.
The vertically opposite angles are $\angle1$ and $\angle3$, $\angle2$ and $\angle4$, $\angle5$ and $\angle7$, $\angle6$ and $\angle8$.
Find the value of $x$:
1.
Since $l\parallel m$, $x = 65^{\circ}$ (corresponding angles).
2.
Since $l\parallel m$, $x=70^{\circ}$ (alternate interior angles).
3.
The angle adjacent to $130^{\circ}$ on line $l$ is $180 - 130=50^{\circ}$. Since $l\parallel m$, $x = 50^{\circ}$ (corresponding angles).
4.
The angle adjacent to $110^{\circ}$ on line $m$ is $180 - 110 = 70^{\circ}$. Since $l\parallel m$, $x=70^{\circ}$ (corresponding angles).
Justify:
Let the angle $\theta>90^{\circ}$. Its supplementary angle $\beta=180-\theta$.
Since $\theta>90^{\circ}$, then $180-\theta<90^{\circ}$. So the supplementary angle of an angle greater than $90^{\circ}$ is less than $90^{\circ}$.
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Fill - in - the - blanks:
- two
- $135^{\circ}$
- linear - pair
- three
- $36^{\circ}$
- $90^{\circ}$
Do as directed:
- (a) corresponding angles; (b) vertically opposite angles; (c) alternate interior angles; (d) adjacent angles
- $90^{\circ}$
In the adjoining figure:
- $\angle3$ and $\angle5$, $\angle4$ and $\angle6$
- $\angle1$ and $\angle5$, $\angle2$ and $\angle6$, $\angle3$ and $\angle7$, $\angle4$ and $\angle8$
- $\angle1$ and $\angle3$, $\angle2$ and $\angle4$, $\angle5$ and $\angle7$, $\angle6$ and $\angle8$
Find the value of $x$:
- $65^{\circ}$
- $70^{\circ}$
- $50^{\circ}$
- $70^{\circ}$
Justify:
The supplementary angle is less than $90^{\circ}$ because if $\theta>90^{\circ}$, then $180 - \theta<90^{\circ}$.