Question

amateur radio operators in the united states can transmit on several bands. one of those bands consists of radio waves with a wavelength near 40.m. calculate the frequency of these radio waves.
round your answer to 2 significant digits.

mhz

Explanation:

Step1: Recall the wave - speed formula

The speed of an electromagnetic wave is given by \(c = \lambda f\), where \(c = 3\times10^{8}\space m/s\) (speed of light in vacuum), \(\lambda\) is the wavelength, and \(f\) is the frequency.
We need to solve for \(f\), so \(f=\frac{c}{\lambda}\).

Step2: Substitute the values

Given \(\lambda = 40\space m\) and \(c = 3\times 10^{8}\space m/s\).

$$ f=\frac{3\times 10^{8}\space m/s}{40\space m} $$

$$ f = 7.5\times10^{6}\space Hz $$

Step3: Convert to MHz

Since \(1\space MHz=10^{6}\space Hz\), then \(f = 7.5\space MHz\).

Answer:

\(7.5\)