Question

alessandro wrote the quadratic equation -6 = x² + 4x - 1 in standard form. what is the value of c in his new equation?
○ c = -6
○ c = -1
○ c = 5
○ c = 7

Explanation:

Step1: Recall standard quadratic form

The standard form of a quadratic equation is \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants.

Step2: Rewrite the given equation

Start with the equation \(-6 = x^2 + 4x - 1\). To convert it to standard form, add 6 to both sides of the equation:

$$
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$$

In the standard form \(x^2 + 4x + 5 = 0\), comparing with \(ax^2 + bx + c = 0\), we have \(a = 1\), \(b = 4\), and \(c = 5\).

Answer:

\(c = 5\) (corresponding to the option \(c = 5\))