Question

2 an airplane moving at 127.3 m/s north encounters a headwind moving at 22.9 m/s south. what is the resultant velocity of the airplane? 129 m/s north 104 m/s south 150 m/s north 104 m/s north

Explanation:

Step1: Define the directions

Let north be the positive direction. Then the velocity of the airplane \(v_{plane}=127.3\ m/s\) (positive) and the velocity of the head - wind \(v_{wind}=- 22.9\ m/s\) (negative as it is in the south direction).

Step2: Calculate the resultant velocity

The resultant velocity \(v = v_{plane}+v_{wind}\).
Substitute the values: \(v=127.3+( - 22.9)\).
\(v = 127.3-22.9\).
\(v=104.4\approx104\ m/s\). Since the result is positive, the direction is north.

Answer:

104 m/s north