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an advertisement for a speed - reading course claimed that the \average…

Question

an advertisement for a speed - reading course claimed that the \average\ reading speed for people com data for the reading speeds per minute for a sample of 24 people who completed the course. complete 1000 750 800 1000 900 850 1050 1000 1050 800 1000 850 700 750 650 850 900 950 600 1100 950 1100 750 650 b. there is no mode. what is the midrange? choose the correct answer below, and, if necessary fill in the answer box to complete y a. the midrange is 850. (round to the nearest whole number as needed.) b. there is no midrange. b. what measure of central tendency was given in the advertisement? a. mode b. median c. mean d. midrange

Explanation:

Step1: Recall the formula for midrange

The midrange is calculated as $\frac{\text{Minimum value}+\text{Maximum value}}{2}$.

Step2: Identify the minimum and maximum values

From the data: Minimum value = $600$, Maximum value = $1100$.

Step3: Calculate the midrange

$$\frac{600 + 1100}{2}=\frac{1700}{2}=850$$

Answer:

A. The midrange is $850$.