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add. \\(2 + 6i) + (4 - 4i)\\ \\(2 + 6i) + (4 - 4i) = \\square\\ (type y…

Question

add.

\\(2 + 6i) + (4 - 4i)\\

\\(2 + 6i) + (4 - 4i) = \square\\ (type your answer in the

Explanation:

🆕 New Concept Discovered: Operations with Complex Numbers
Combine real parts with real parts, and imaginary parts with imaginary parts.

Step 1: Group like terms

To add complex numbers, we remove the parentheses and group the real parts together and the imaginary parts together.

$$ (2 + 6i) + (4 - 4i) = 2 + 6i + 4 - 4i $$

Group the real numbers:

$$ 2 + 4 $$

Group the imaginary numbers (the terms with \(i\)):

$$ 6i - 4i $$

Step 2: Simplify

Add the real parts and combine the imaginary parts:

$$ (2 + 4) + (6i - 4i) $$
$$ 6 + 2i $$

Answer:

\(6 + 2i\)