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ad and mn are chords that intersect at point b. what is the length of l…

Question

ad and mn are chords that intersect at point b. what is the length of line segment mn? 24 units 6 units 4 units 18 units

Explanation:

Step1: Apply the Chords - Intersecting Theorem

When two chords intersect each other inside a circle, the products of the lengths of their segments are equal. So, \(AB\times BD=MB\times BN\).
Given \(AB = 9\), \(BD=x + 1\), \(MB=x - 1\), and \(BN = 15\). Then \(9\times(x + 1)=(x - 1)\times15\).

Step2: Solve the Equation for \(x\)

Expand the equation: \(9x+9 = 15x-15\).
Subtract \(9x\) from both sides: \(9=15x - 9x-15\), so \(9 = 6x-15\).
Add \(15\) to both sides: \(9 + 15=6x\), i.e., \(24 = 6x\).
Divide both sides by \(6\): \(x=\frac{24}{6}=4\).

Step3: Calculate the Length of \(MN\)

Since \(MN=(x - 1)+15\), substitute \(x = 4\) into the formula. \(MN=(4 - 1)+15\).
\(MN=3 + 15=18\)

Answer:

18 units