Question

x is an acute angle. find the value of x in deg
cos(x)=\frac{\sqrt{2}}{2}
x=\square^{circ}

Explanation:

Step1: Recall the cosine value of special angles

We know that $\cos(45^{\circ})=\frac{\sqrt{2}}{2}$.

Step2: Determine the value of \(x\)

Since \(\cos(x)=\frac{\sqrt{2}}{2}\) and \(x\) is an acute angle, then \(x = 45^{\circ}\).

Answer:

\(45\)