Question

activity: monohybrid cross
8 parts 1.88 of 5 points
the result of the following cross indicates that the genotype of the female parent is _.
p generation
phenotypes: wild type head top flat head top
f, generation
phenotype: all wild type head top
r
rr
r
rr
rr

Explanation:

Step1: Analyze the inheritance pattern

In a monohybrid cross, if one parent has a recessive trait (flat head top, assuming \(r\) represents the recessive allele) and the \(F_1\) generation shows only the dominant trait (wild - type head top).

Step2: Determine the female parent's genotype

Since the male parent (flat head top) has a genotype of \(rr\) (as it shows the recessive phenotype). For all \(F_1\) offspring to show the dominant phenotype, the female parent must be homozygous dominant. If the female parent was heterozygous (\(Rr\)), there would be a \(50\%\) chance of offspring showing the recessive phenotype. If it was \(R\) (not a valid genotype notation for diploid organisms in this context) or \(r\) (recessive, would show flat head top) or \(rr\) (recessive, would show flat head top), the \(F_1\) generation would not all be wild - type.

Answer:

RR