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δacb ~ δefd z = ?°

Question

δacb ~ δefd
z = ?°

Explanation:

Step1: Recall property of similar triangles

Corresponding angles of similar triangles are equal.

Step2: Identify corresponding angles

In $\triangle ACB\sim\triangle EFD$, $\angle B$ corresponds to $\angle D$, $\angle C$ corresponds to $\angle F$, $\angle A$ corresponds to $\angle E$.

Step3: Calculate angle measure

In $\triangle ACB$, $\angle A=180^{\circ}-65^{\circ}-55^{\circ}=60^{\circ}$. Since $\angle A=\angle E = z$, $z = 60^{\circ}$.

Answer:

$60$