Question

1. a 95 kg object is initially traveling at a velocity of 13 m/s east. if a constant force of 1200 n due east is applied to the body for 5.0 s, what is the objects final speed?

Explanation:

Step1: Calculate acceleration using Newton's second law

According to Newton's second law \(F = ma\), where \(F = 1200\space N\), \(m=95\space kg\). So, \(a=\frac{F}{m}=\frac{1200}{95}\approx12.63\space m/s^{2}\)

Step2: Use the kinematic equation \(v = u+at\)

Given \(u = 13\space m/s\), \(a\approx12.63\space m/s^{2}\), \(t = 5.0\space s\). Then \(v=13+12.63\times5.0\)

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Answer:

\(76.16\space m/s\)