QUESTION IMAGE
Question
8x - 12 ≥ -36
+12 | +12
8x ≥ -24
(8x)/8 ≥ (-24)/8
x ≥ -3
Step1: Add 12 to both sides
To isolate the term with \( x \), we add 12 to both sides of the inequality \( 8x - 12 \geq -36 \). This gives \( 8x - 12 + 12 \geq -36 + 12 \), which simplifies to \( 8x \geq -24 \).
Step2: Divide both sides by 8
To solve for \( x \), we divide both sides of the inequality \( 8x \geq -24 \) by 8. So, \( \frac{8x}{8} \geq \frac{-24}{8} \), which simplifies to \( x \geq -3 \).
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\( x \geq -3 \)