Question

is (-8, -2) a solution to this system of equations?
$y = \frac{1}{2}x + 2$
$y = -2$
yes
no

Explanation:

Step1: Substitute x and y values

Substitute $x = - 8$ and $y=-2$ into $y=\frac{1}{2}x + 2$.

Step2: Calculate the right - hand side

When $x=-8$, $\frac{1}{2}x + 2=\frac{1}{2}\times(-8)+2=-4 + 2=-2$.

Step3: Compare with left - hand side

The left - hand side is $y=-2$. Since the left - hand side equals the right - hand side when substituting $x=-8$ and $y = - 2$ into $y=\frac{1}{2}x+2$, and $y=-2$ is also satisfied by the second equation.

Answer:

yes