Question

1. a 75 kg skydiver pulls their parachute and begins falling at a constant velocity of 3 m/s. what is the drag force on the skydiver? clear all 25 n 77 n 735 n 225 n

Explanation:

Step1: Identify forces at equilibrium

When the skydiver is falling at a constant velocity, the net - force acting on the skydiver is zero according to Newton's first law. The two main forces acting on the skydiver are the gravitational force ($F_g$) and the drag force ($F_d$). So, $F_{net}=F_d - F_g=0$, which means $F_d = F_g$.

Step2: Calculate the gravitational force

The formula for gravitational force is $F_g=mg$, where $m = 75\ kg$ and $g = 9.8\ m/s^2$. Then $F_g=75\times9.8 = 735\ N$. Since $F_d = F_g$, the drag force $F_d=735\ N$.

Answer:

735 N