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6x + 5, 3, 2, 4, 5, 7, 6, 2x + 69, what is the value of x?

Question

6x + 5, 3, 2, 4, 5, 7, 6, 2x + 69, what is the value of x?

Explanation:

Step1: Identify Alternate Exterior Angles

Angles \(6x + 5\) and \(2x + 69\) are alternate exterior angles, so they are equal. Thus, \(6x + 5 = 2x + 69\).

Step2: Solve for \(x\)

Subtract \(2x\) from both sides: \(6x - 2x + 5 = 2x - 2x + 69\) → \(4x + 5 = 69\).
Subtract 5 from both sides: \(4x + 5 - 5 = 69 - 5\) → \(4x = 64\).
Divide by 4: \(\frac{4x}{4} = \frac{64}{4}\) → \(x = 16\).

Answer:

\(16\)