Question

a 65 - ton monolith is transported on a causeway that is 4000 feet long and has a slope of about 4.8°. how much force parallel to the incline would be required to hold the monolith on this causeway? a force of tons is required to hold the monolith on the causeway. (round to the nearest tenth as needed.)

Explanation:

Step1: Identify the formula for force on an incline

The force \( F \) parallel to the incline required to hold an object of weight \( W \) on an incline with angle \( \theta \) is given by \( F = W \sin\theta \), where \( W = 65 \) tons and \( \theta = 4.8^\circ \).

Step2: Calculate the sine of the angle

First, find \( \sin(4.8^\circ) \). Using a calculator, \( \sin(4.8^\circ) \approx 0.0837 \).

Step3: Compute the force

Multiply the weight by the sine of the angle: \( F = 65 \times 0.0837 \approx 5.4405 \).

Step4: Round to the nearest tenth

Rounding \( 5.4405 \) to the nearest tenth gives \( 5.4 \).

Answer:

\( 5.4 \)