Question

1. a 60-kg physics student would weigh 1500 n on the surface of planet x. what is the magnitude of the acceleration due to gravity on the surface of planet x?
2. 0.038 m/s²
3. 6.1 m/s²
4. 9.8 m/s²
5. 25 m/s²

1. earth’s mass is approximately 81 times the mass of the moon. if earth exerts a gravitational force of magnitude f on the moon, the magnitude of the gravitational force of the moon on earth is
2. f
3. f/81
4. 9f
5. 81f

1. an object weighs 100 newtons on earth’s surface. when it is moved to a point one earth radius above earth’s surface, it will weigh
2. 25 n
3. 50 n
4. 100 n
5. 400 n

the slope of the graph represents the

1. acceleration due to gravity
2. universal gravitational constant
3. momentum of objects
4. weight of objects

1. a person weighing 785 newtons on the surface of earth would weigh 298 newtons on the surface of mars. what is the magnitude of the gravitational field strength on the surface of mars?
2. 2.63 n/kg
3. 3.72 n/kg
4. 6.09 n/kg
5. 9.81 n/kg

Explanation:

Step1: Recall weight formula

Weight $W = m \cdot g$, so $g = \frac{W}{m}$

Step2: Substitute values

$g = \frac{1560\ \text{N}}{60\ \text{kg}} = 26\ \text{m/s}^2$

By Newton's third law, forces between two objects are equal and opposite. Earth and Moon exert equal gravitational forces on each other.

Step1: Find mass of person

On Earth: $m = \frac{W_{\text{Earth}}}{g_{\text{Earth}}} = \frac{785\ \text{N}}{9.81\ \text{N/kg}} \approx 80.02\ \text{kg}$

Step2: Calculate Mars' gravitational field

$g_{\text{Mars}} = \frac{W_{\text{Mars}}}{m} = \frac{298\ \text{N}}{80.02\ \text{kg}} \approx 3.72\ \text{N/kg}$

The graph plots gravitational force vs. mass. Slope = force/mass = gravitational acceleration (since $F=mg$).

Answer:

1. 26 m/s²