Question

a 50 kg skiier slows down from 6.0 m/s to 2.0 m/s (in the same direction). what is the momentum change of the skiier?
-300 kg·m/s
-600 kg·m/s
-12.5 kg·m/s
-200 kg·m/s
question 9
1 pts
n 8 kg object is moving to the right at 5 m/s. a second object
th a mass of 3 kg is in its path and is moving at 10 m/s to the
t.

Explanation:

Step1: Recall momentum formula

Momentum \( p = mv \), change in momentum \( \Delta p = m(v_f - v_i) \).

Step2: Identify values

Mass \( m = 50 \, \text{kg} \), initial velocity \( v_i = 6.0 \, \text{m/s} \), final velocity \( v_f = 2.0 \, \text{m/s} \).

Step3: Calculate change in momentum

Substitute into formula: \( \Delta p = 50(2.0 - 6.0) = 50(-4.0) = -200 \, \text{kg·m/s} \).

Answer:

-200 kg·m/s