Question

4y + \frac{2}{10} + 8n + \frac{4}{10} + 3y - 4n = \square (use the operation symbols in the math

Explanation:

Step1: Combine like terms for y

We have \(4y\) and \(3y\). Adding them together: \(4y + 3y = 7y\)

Step2: Combine like terms for n

We have \(8n\) and \(-4n\). Adding them together: \(8n - 4n = 4n\)

Step3: Combine the constant fractions

We have \(\frac{2}{10}\) and \(\frac{4}{10}\). Adding them together: \(\frac{2}{10}+\frac{4}{10}=\frac{6}{10}=\frac{3}{5}\)

Step4: Combine all the results

Now, we combine the results from the previous steps: \(7y + 4n+\frac{3}{5}\)

Answer:

\(7y + 4n+\frac{3}{5}\)