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m∠1 = 1 + 4x and m∠2 = 3x + 5. find m∠ywx.

Question

m∠1 = 1 + 4x and m∠2 = 3x + 5. find m∠ywx.

Explanation:

Step1: Set up the equation

Since \(\angle1\) and \(\angle2\) are equal (assuming \(WP\) is an angle - bisector, though the problem should state this clearly; common in geometry angle - bisector problems). So \(1 + 4x=3x + 5\).

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Step2: Calculate \(m\angle YWX\)

\(m\angle YWX=m\angle1 + m\angle2=(1 + 4x)+(3x + 5)=7x+6\).
Substitute \(x = 4\) into \(7x + 6\).

$$7\times4+6=28 + 6=34$$

Answer:

\(m\angle YWX = 34^{\circ}\)