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Question
3x - 4y = 8
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(coordinate plane with x-axis from -10 to 10 and y-axis from -2 to 10)
Step1: Find x-intercept (y=0)
Substitute \( y = 0 \) into \( 3x - 4y = 8 \):
\( 3x - 4(0) = 8 \)
\( 3x = 8 \)
\( x = \frac{8}{3} \approx 2.67 \)? Wait, no—wait, maybe better to find integer points. Wait, let's solve for y-intercept (x=0) first.
Step2: Find y-intercept (x=0)
Substitute \( x = 0 \) into \( 3x - 4y = 8 \):
\( 3(0) - 4y = 8 \)
\( -4y = 8 \)
\( y = -2 \). So the y-intercept is \( (0, -2) \).
Step3: Find another point (x=4)
Substitute \( x = 4 \) into \( 3x - 4y = 8 \):
\( 3(4) - 4y = 8 \)
\( 12 - 4y = 8 \)
\( -4y = -4 \)
\( y = 1 \). So point \( (4, 1) \).
Now, plot \( (0, -2) \) and \( (4, 1) \), then draw a line through them.
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To graph \( 3x - 4y = 8 \):
- Find the y - intercept: Set \( x = 0 \), solve \( -4y = 8 \) → \( y = -2 \), so point \( (0, -2) \).
- Find another point: Set \( x = 4 \), solve \( 12 - 4y = 8 \) → \( y = 1 \), so point \( (4, 1) \).
- Use the "Line" tool to draw a line through \( (0, -2) \) and \( (4, 1) \) (or other two points from the equation).