Question

1. the moon does not orbit earth in a circular path as the distance between these two objects changes. during a super moon, the moon is at its closest point to earth (356,761,000 m). determine the effects of earths gravitational field on the moon at this point, known as the perigee. earths mass is 6 x 10^24 kg.

3.14 x 10^3 n/kg
3.14 x 10^-4 n/kg
3.14 x 10^-3 n/kg
3.14 n/kg

Explanation:

Step1: Recall the formula for gravitational field strength

The formula for gravitational field strength \(g\) is \(g=\frac{GM}{r^{2}}\), where \(G = 6.67\times10^{- 11}\space Nm^{2}/kg^{2}\) (universal gravitational constant), \(M\) is the mass of the Earth, and \(r\) is the distance from the Earth to the moon.

Step2: Substitute the given values

Given \(M = 6\times10^{24}\space kg\) and \(r=356761000\space m\approx3.56761\times 10^{8}\space m\)

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Answer:

3.14 x 10⁻³ N/kg