Question

1. ( x = 6 + 2y )\\( -3x + 14y = -18 )

Explanation:

Step1: Substitute x into the second equation

Given \( x = 6 + 2y \), substitute \( x \) into \( -3x + 14y = -18 \). So we get \( -3(6 + 2y) + 14y = -18 \).

Step2: Simplify the equation

Expand the left - hand side: \( -18-6y + 14y=-18 \). Combine like terms: \( -18 + 8y=-18 \).

Step3: Solve for y

Add 18 to both sides of the equation: \( 8y=-18 + 18=0 \), then \( y = 0\div8 = 0 \).

Step4: Solve for x

Substitute \( y = 0 \) into \( x = 6+2y \), we get \( x=6 + 2\times0=6 \).

Answer:

The solution of the system of equations is \( x = 6,y = 0 \)