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QUESTION IMAGE

n) (2x - 4)° (3x - 6)° (x + 22)°

Question

n)
(2x - 4)°
(3x - 6)°
(x + 22)°

Explanation:

Step1: Use the triangle - angle - sum theorem

The sum of the interior angles of a triangle is \(180^{\circ}\). So, \((2x - 4)+(3x - 6)+(x + 22)=180\).

Step2: Combine like terms

First, combine the \(x\) terms: \(2x+3x + x=6x\). Then, combine the constant terms: \(-4-6 + 22=12\). The equation becomes \(6x+12 = 180\).

Step3: Solve for \(x\)

Subtract \(12\) from both sides: \(6x=180 - 12\), so \(6x=168\). Divide both sides by \(6\): \(x=\frac{168}{6}=28\).

Answer:

\(x = 28\)