Question

v² = u² + 2as
where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the d
find v when u is 8 m/s, a is 3 m/s², and s is 19 meters.
○ a. 15 m
○ b. 13 m
○ c. √130 m
○ d. √178 m
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Explanation:

Step1: Substitute the values into the formula

Given \(u = 8\), \(a=3\), \(s = 19\), substitute into \(v^{2}=u^{2}+2as\).
\(v^{2}=8^{2}+2\times3\times19\)

Step2: Calculate \(u^{2}\) and \(2as\)

\(8^{2}=64\), \(2\times3\times19 = 114\)
So \(v^{2}=64 + 114\)

Step3: Sum the values

\(v^{2}=178\)

Step4: Solve for \(v\)

Take the square root of both sides: \(v=\sqrt{178}\)

Answer:

D. \(\sqrt{178}\text{ m}\)