Question

v² = u² + 2as
where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the accelerati
find v when u is 9 m/s, a is 7 m/s², and s is 28 meters.
○ a. √473 m/s
○ b. √410 m/s
○ c. 20 m/s
○ d. √178 m/s
reset selection

Explanation:

Step1: Substitute the given values into the formula

Given \(u = 9\space m/s\), \(a=7\space m/s^{2}\), \(s = 28\space m\) into \(v^{2}=u^{2}+2as\).

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Step2: Calculate each term

First, calculate \((9)^{2}=81\). Then calculate \(2\times7\times28 = 392\).

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Step3: Solve for \(v\)

Take the square root of both sides. Since \(v\) represents velocity (a non - negative quantity in the context of magnitude for this formula), \(v=\sqrt{473}\space m/s\)

Answer:

A. \(\sqrt{473}\space m/s\)