Question

5/29
pass\tfail
defective\t5\t24
non - defective\t208\t9

1. find the probability that a non - defective part \passes.\

Explanation:

Step1: Identify relevant counts

From the table, number of non - defective parts that pass is 208, and total number of non - defective parts is \(208 + 9=217\).

Step2: Calculate probability

Probability \(P=\frac{\text{Number of non - defective parts that pass}}{\text{Total number of non - defective parts}}=\frac{208}{217}\) (simplify if needed, but as per the problem, we can present it as is or calculate the decimal. \(\frac{208}{217}\approx0.9585\))

Answer:

\(\frac{208}{217}\) (or approximately \(0.9585\))