Question

1. find the color of light whose frequency is 5.21x10^{14} hz.

Explanation:

Step1: Calculate the wavelength

We know the formula \(c = \lambda f\), where \(c = 3\times10^{8}\space m/s\) (speed of light), \(f = 5.21\times 10^{14}\space Hz\) (frequency). Rearranging for \(\lambda\), we get \(\lambda=\frac{c}{f}\).
Substituting the values: \(\lambda=\frac{3\times 10^{8}}{5.21\times 10^{14}}\)

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Step2: Determine the color

Looking at the visible light spectrum:

• Red: \(620 - 750\space nm\)
• Orange: \(590 - 620\space nm\)
• Yellow: \(570 - 590\space nm\)
• Green: \(495 - 570\space nm\)
• Blue: \(450 - 495\space nm\)
• Violet: \(380 - 450\space nm\)

Since \(576\space nm\) falls in the range \(570 - 590\space nm\)

Answer:

Yellow