Question

1. 28 g of iron shot is added to a graduated cylinder containing 40 ml of water. the water level rises to the 44 ml mark. from this information, calculate the density of iron.

Explanation:

Step1: Find the volume of iron shot

The initial volume of water is 40 mL, and the final volume (water + iron shot) is 44 mL. The volume of the iron shot ($V$) is the difference between the final and initial volumes.
$V = 44\ mL - 40\ mL = 4\ mL$
Since 1 mL is equal to 1 $cm^3$, the volume of the iron shot is 4 $cm^3$.

Step2: Calculate the density of iron

Density ($
ho$) is given by the formula $
ho=\frac{m}{V}$, where $m$ is the mass and $V$ is the volume. The mass of the iron shot ($m$) is 28 g, and the volume ($V$) is 4 $cm^3$.
$
ho=\frac{28\ g}{4\ cm^3}=7\ g/cm^3$

Answer:

The density of iron is $7\ g/cm^3$ (or $7000\ kg/m^3$).