QUESTION IMAGE
Question
- simplify: $-4 + |5 + (-2)| + |-(-7)|$
a. -8
b. -5
c. 6
d. 10
- simplify: $-3 \cdot 4 + 6 - 4 \div 2$
a. -24
b. -17
c. -8
d. 7
- simplify: $(2x + 1)3 + 4x$
a. $10x + 1$
b. $9x$
c. $13x$
d. $10x + 3$
- factor completely: $18d^4 - 24d^3$
a. $6d^3(3d - 4)$
b. $6d^3(12d - 18)$
c. $6(3d^4 - 4d^3)$
d. $2d^3(9d - 12)$
- factor completely: $8x^3 - 2x^2 + 4x$
a. $(2x + 1)(4x - 4)$
b. $4x^3(2x + 2)$
c. $2x(4x^2 + x + 2)$
d. $(4x + 2)(2x + 2)$
- factor completely: $5x^3 + 15x^2 + 10x$
a. $(x + 5)(5x - 2)$
b. $5x(x^2 + 3x + 2)$
c. $x(5x^2 + 15x + 10)$
d. $(6x + 2)(x + 5)$
Question 26:
Step1: Simplify inside absolute values
First, calculate the expressions inside the absolute value symbols. For \(|5 + (-2)|\), we have \(5 + (-2)=3\), so \(|3| = 3\). For \(|-(-7)|\), we know that \(-(-7)=7\), so \(|7| = 7\).
Step2: Substitute and simplify the expression
Now substitute these values back into the original expression: \(-4+|5 + (-2)|+|-(-7)|=-4 + 3+7\). Now, add the numbers: \(-4+3=-1\), and then \(-1 + 7 = 6\).
Step1: Follow the order of operations (PEMDAS/BODMAS)
First, perform the multiplications and divisions from left to right. We have \(-3\cdot4=-12\) and \(4\div2 = 2\).
Step2: Substitute and simplify the expression
Now substitute these values back into the original expression: \(-3\cdot4 + 6-4\div2=-12 + 6-2\). Now, perform the additions and subtractions from left to right: \(-12+6=-6\), and then \(-6-2=-8\).
Step1: Distribute the multiplication (if needed) and combine like terms
First, distribute the 3 in \((2x + 1)3\): \(3\times2x=6x\) and \(3\times1 = 3\), so \((2x + 1)3=6x+3\).
Step2: Combine like terms
Now, add \(4x\) to \(6x + 3\): \(6x+3+4x=(6x + 4x)+3=10x+3\).
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C. 6